Difference between revisions of "@notsosureofit Hypothesis"
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[0,1]=3.83, [1,1]=1.84, [2,1]=3.05, [0,2]=7.02, [1,2]=5.33, [1,3]=8.54, [0,3]=10.17, [2,2]=6.71, etc. | [0,1]=3.83, [1,1]=1.84, [2,1]=3.05, [0,2]=7.02, [1,2]=5.33, [1,3]=8.54, [0,3]=10.17, [2,2]=6.71, etc. | ||
| − | Here is a table [http://wwwal.kuicr.kyoto-u.ac.jp/www/accelerator/a4/besselroot.htmlx] to 15 digits precision for the roots of the cylindrical Bessel functions X[sub m,n] and for the roots of its derivative X'[subm,n] from m=0 to m=10, and from n=1 to n=5 | + | |
| + | * Here is a table [http://wwwal.kuicr.kyoto-u.ac.jp/www/accelerator/a4/besselroot.htmlx] to 15 digits precision for the roots of the cylindrical Bessel functions X[sub m,n] and for the roots of its derivative X'[subm,n] from m=0 to m=10, and from n=1 to n=5 | ||
| + | |||
Rotate the dispersion relation of the cavity into doppler frame to get the Doppler shifts, that is to say, look at the dispersion curve intersections of constant wave number instead of constant frequency. | Rotate the dispersion relation of the cavity into doppler frame to get the Doppler shifts, that is to say, look at the dispersion curve intersections of constant wave number instead of constant frequency. | ||
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<math>W = \cfrac{hf}{c^2}g</math> | <math>W = \cfrac{hf}{c^2}g</math> | ||
| − | where | + | where we make the connection via the Equivalence Principle that the acceleration of a photon seen in the rest frame is that which is balanced out in the accelerated frame. That is, the dispersion of the tapered cavity reduces to zero (along the axis) in that accelerated frame of reference. |
| + | |||
| + | Such that: | ||
<math>W = T = \cfrac{h}{L}\Delta f</math> | <math>W = T = \cfrac{h}{L}\Delta f</math> | ||
| − | + | We identify that as the thrust per photon: | |
<!-- T = (h/(2*L*f))*(c/(2*π))^2*X^2*((1/Rs^2)-(1/Rb^2)) --> | <!-- T = (h/(2*L*f))*(c/(2*π))^2*X^2*((1/Rs^2)-(1/Rb^2)) --> | ||
Revision as of 07:58, 29 May 2015
The proposition that dispersion caused by an accelerating frame of reference implied an accelerating frame of reference caused by a dispersive cavity resonator. (to 1st order using massless, perfectly conducting cavity)
Starting with the expressions for the frequency of a cylindrical RF cavity:
[math]f = \cfrac{c}{2π}\sqrt{(\cfrac{X}{R})^2+(\cfrac{pπ}{L})^2}[/math]
For TM modes, X = X[sub m,n] = the n-th zero of the m-th Bessel function. [1,1]=3.83, [0,1]=2.40, [0,2]=5.52 [1,2]=7.02, [2,1]=5.14, [2,2]=8.42, [1,3]=10.17, etc.
and for TE modes, X = X'[subm,n] = the n-th zero of the derivative of the m-th Bessel function. [0,1]=3.83, [1,1]=1.84, [2,1]=3.05, [0,2]=7.02, [1,2]=5.33, [1,3]=8.54, [0,3]=10.17, [2,2]=6.71, etc.
- Here is a table [1] to 15 digits precision for the roots of the cylindrical Bessel functions X[sub m,n] and for the roots of its derivative X'[subm,n] from m=0 to m=10, and from n=1 to n=5
Rotate the dispersion relation of the cavity into doppler frame to get the Doppler shifts, that is to say, look at the dispersion curve intersections of constant wave number instead of constant frequency.
[math]\Delta f = \cfrac{1}{2f}(\cfrac{c}{2π})^2X^2(\cfrac{1}{Rs^2}-\cfrac{1}{Rb^2})[/math]
This is a cylindrical approximation and could be replaced with a tapered dielectric index of refraction in a cylindrical cavity.
and from there the expression for the acceleration g from:
[math]g = \cfrac{c^2}{L}\cfrac{\Delta f}{f}[/math]
such that:
[math]g = \cfrac{c^2}{2Lf^2}(\cfrac{c}{2π})^2X^2(\cfrac{1}{Rs^2}-\cfrac{1}{Rb^2})[/math]
This is the acceleration at which the dispersion of the tapered cavity is balanced out by the dispersion due to its acceleration.
Using the "weight" of the photon in the accelerated frame from:
[math]W = \cfrac{hf}{c^2}g[/math]
where we make the connection via the Equivalence Principle that the acceleration of a photon seen in the rest frame is that which is balanced out in the accelerated frame. That is, the dispersion of the tapered cavity reduces to zero (along the axis) in that accelerated frame of reference.
Such that:
[math]W = T = \cfrac{h}{L}\Delta f[/math]
We identify that as the thrust per photon:
[math]T = \cfrac{h}{2Lf}(\cfrac{c}{2π})^2X^2(\cfrac{1}{Rs^2}-\cfrac{1}{Rb^2})[/math]
If the number of photons is
[math]\cfrac{P}{hf}(\cfrac{Q}{2πf})[/math]
then the total thrust is
[math]NT = \cfrac{PQ}{4πLf^3}(\cfrac{c}{2π})^2X^2(\cfrac{1}{Rs^2}-\cfrac{1}{Rb^2})[/math]
